(x^2)+(1.8*10^-5)x-3.78*10^-8=0

Solution for (x^2)+(1.8*10^-5)x-3.78*10^-8=0 equation:

(x^2)+(1.8*10^-5)x-3.78*10^-8=0

We add all the numbers together, and all the variables

x^2+(1.8*10^-5)x=0

We multiply parentheses

x^2+18x^2-5x=0

We add all the numbers together, and all the variables

19x^2-5x=0

a = 19; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·19·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*19}=\frac{0}{38}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*19}=\frac{10}{38}
=5/19
$